Question

LCD Help!!!!

Answer 1

hint : a^2-7a+6 = (a-1)(a-6)
a^2-36 = (a+6)(a-6)
find LCM of both

Answer 2

LCM =2?

Answer 3

why ?

Answer 4

because 2 can be multiplied evenly to make 6... i think?

Answer 5

this is expression algebaraic, so we can calculate LCM of each denominator above can be :
(a-1)(a-6)(a+6)

Answer 6

algebraic*

Answer 7

i have that.... but do we combine that or do we leave as is???

Answer 8

one of method to calculate LCM is using factorization, can u use that operation?

Answer 9

i factored them both im gonna show you what i did....

a^2-7a+6 = (a-2)(a+3)
a^2-36 = (a)(-3)(3) (a)(2)(3)

then i thought the second one should be factored differently so i did
a^2-7a+6 = (a-2)(a+3)
a^2-36 = (a-6) (a+6)

Answer 10

ok, nopes...
still wrong in the first term.
to find factor of a^2-7a+6, u must think number when multiplied both get +6 and when addited both get -7. so the numbers are -1 and -6, right ?
so, its factor is (x-1)(x-6)

Answer 11

oh okay

Answer 12

so, ur problem just to find LCD ? not simplicated after that ?

Answer 13

yes

Answer 14

if it, (a-1)(a-6)(a+6) is the answer

Answer 15

okay thanks!!!!!

Answer 16

welcome