Question

is the inverse sine of sine of (-(4pi)/9)) equal pi/9?

Answer 1

sin(-x) = -sinx

Answer 2

-sin^-1 (sin 4pie/9)

Answer 3

so -4pie/9

Answer 4

Why not just -pi/9?

Answer 5

But
pi/9 is in that range?

Answer 6

Oh. Wait It is.

Answer 7

What is?

Answer 8

lol.
So yeah \[\frac{-4 \pi }{9} \in [\frac{-\pi}{2}, \frac{\pi}{2}] =>\sin^{-1}(\sin(\frac{-4 \pi}{9}))=\frac{-4 \pi}{9} \]

Answer 9

\[-.444 \pi \in [-.5 \pi , .5 \pi]\]
Since
\[-.444 \in [-.5,.5]\]

Answer 10

-4/9 is approximately -.444 :)