Question

Okay i have no idea how to do this, and nobody at my house knows so please answer :)
"Write an equation of the line parallel to given line containing C."
12. C(6,-2);y= -3/2x+6
Then another ones,
"Write an equation of line perpendicular to the given line contains P."
1.P(6,6);y=2/3x
2.P(4,4);y=-2x-8

Answer 1

Helppp :(

Answer 2

slope of \(y=-\frac{3}{2}x+6\) is \(-\frac{3}{2}\)
your job is to find the equation of the line with slope \(-\frac{3}{2}\) through the point \((6,-2)\)
the point-slope formula
\[y=y_1=m(x-x_1)\] will give it to you
use \(m=\frac{3}{x},x_1=6,y_1=-2\)

Answer 3

oops i meant \(m=-\frac{3}{2}\)

Answer 4

The equation that you are looking for y=mx+b
Parallel with line y=-3/2x+6
Therefore m=-3/2
Now your line looks like y= -3/2x +b. this line passes the point C(6,-2)next step we have
-2=-3/2(6)+b
-2=-9+b
-2+9=b
b=7
Final you line equaltion is y=-3/2+7 this line parallel iwth the line y=-3/2x+6 and also passes the point C(6,-2)

Answer 5

so u will get y=-3/2x+7 solving using the point slope formula

Answer 6

either way will work

Answer 7

How do i know if it's parrell?

Answer 8

Because parallel lines have same slopes, perpendicular negative reciprocals, and intersecting lines different slopes

Answer 9

Thank you guys! <3

Answer 10

welcomee