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Mathematics 14 Online
OpenStudy (anonymous):

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 +19.6t + 58.8. What is the object's maximum height?

OpenStudy (anonymous):

A. 58.8 B. 194.04 C. 78.4 D. 117.6

OpenStudy (anonymous):

Find the vertex of the parabola.

OpenStudy (anonymous):

If you know any calculus, you can also differentiate that position equation to find velocity and set velocity =0.

OpenStudy (anonymous):

I don't):

OpenStudy (anonymous):

Given an equation in the form, y=ax^2 +bx +c, do you know how to find the vertex of the parabola?

OpenStudy (anonymous):

There are techniques such as completing the square or quadratic formula that will work for that.

OpenStudy (anonymous):

-19.6+39.6+58.8

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