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Solve 4^x-2+1=5
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is that your question? don't you mistype something?
no it's right
i'm confused if you are suppose to move the 1 to the other side of the equal sign
do you know how to answer this
well first you want to get the term with x alone on one side: 4^x-2+1=5 4^x=6 then you take to log of both sides log(4^x)=log(6) by the rule of logs xlog(4)=log(6) x=log(6)/log(4) x=1.292
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the answer should be 3. its 4 to the power of x-2 +1 =5
oh i thought that since there weren't parentheses that the equation was 4^(x) -2+1=5. sorry about that
no worries it's kind of confussing. do you know how to answer this
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