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OpenStudy (anonymous):
Given f(x) = 5x - 6 and g(x) = x2 - 5x + 6, find the function (f - g)(x). Use the ^ key for the exponent. Will someone please help me with this and explain how to get the answer?!..
13 years ago
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jimthompson5910 (jim_thompson5910):
(f - g)(x) = f(x) - g(x)
(f - g)(x) = (5x-6) - (x^2-5x+6)
From here, distribute and combine like terms
13 years ago
OpenStudy (anonymous):
so it would be x^2+6?
13 years ago
jimthompson5910 (jim_thompson5910):
(f - g)(x) = (5x-6) - (x^2-5x+6)
(f - g)(x) = 5x-6 - x^2-5x+6
(f - g)(x) = 5x-6 - x^2+5x-6
What's next?
13 years ago
OpenStudy (anonymous):
cyou would cancel out the 5x's right?
13 years ago
jimthompson5910 (jim_thompson5910):
why would they cancel?
13 years ago
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OpenStudy (anonymous):
cause 5x-5x? I'm not sure this is really confusing me..
13 years ago
jimthompson5910 (jim_thompson5910):
no the negative distributes and changes it to +5x
13 years ago
OpenStudy (anonymous):
oh so then would it be 10x^2-12
13 years ago
jimthompson5910 (jim_thompson5910):
not quite
13 years ago
jimthompson5910 (jim_thompson5910):
(f - g)(x) = 5x-6 - x^2+5x-6
(f - g)(x) =-x^2 + (5x+5x)+ (-6-6)
(f - g)(x) = -x^2 + 10x - 12
13 years ago
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OpenStudy (anonymous):
oh.. I see how you broke it down, I kept canceling them out and i was left with just the x^2 thank you!
13 years ago
jimthompson5910 (jim_thompson5910):
np
13 years ago
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