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Find the domain of each function a. f(x)=x/x^2-9 b. g(x)=3/sqrt of x+7 c. h(x)=sqrt of 5-x
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is the first one \(f(x)=\frac{x}{x^2-9}\) ?
yes
if so, domain is all real numbers except where the denominator is zero set \(x^2-9=0\) and solve for \(x\)
why
for the next two, make sure that a) \(x+7>0\) and b) \(5-x\geq 0\)
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oh, to answer your question, because you cannot divide by \(0\)
so if you write \(\frac{-3}{0}\) it is not a number
@satellite73 Fan me please
Ok, thnx for the useful info
yw
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