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Can someone explain to me logarithmic functions?
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\[e^{3x}=\frac{ 1 }{ 2 }\]
not sure what rule i can use to simplify that
here on the left hand side you have base as "e" so take natural log i.e. ln of both sides as they cancel out
take the ln of both sides then divide by 3...
3x=ln1/2
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ln e^x = x
\[e^{3x}=\frac{ 1 }{ 2 }\]\[3x=\ln(1/2)\]\[x=\frac{ -1 }{ 3 }\ln(2)\]
the book answer is -1/3ln2
whoa?
now put value of ln 1/2 on right side and divide it by 3
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ln(1/2) is negative?
yeah it is...
ok, is there a rule for that??
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