a particles position on the x axis is given by the function x=(t^2 -4t +2)m where t is is in s. where is the particle when v=4.0 (m/s)????

Question

chrisplusian · Answer

so what I did was differentiate the function and got the velocity function 2t-4

chrisplusian · Answer

then I set that equal to 4   "2t-4=4" and solved for t. That gave me t=4. Then I tried to plug that back into the position function and it gave me x=10m. but that answer didn't check with the solution guide, which said x=2m. What did I do wrong?

anonymous · Answer

plugging t=4 back into $\large t^2-4t+2 $  gives you 2.....
$\large 4^2-4(4)+2=16-16+2=2 $

chrisplusian · Answer

woops! THANKS THAT WAS A BAD MOMENT!!!