Question

find the limit of the following questions
lim x^2/(x^2)-9
x->3

lim 4-x/(x^2)-16
x->-4

I got "does not exist" for both questions..
but I don't think it's correct
can anyone help please?!

Answer 1

is the first one this: \(\large\lim_{x \to 3} \frac{x^2}{x^2-9}\) ????

Answer 2

if yes, then you're correct.
but the second one does have a limit...

Answer 3

yea that's the first one
but i can't factorize the second one

Answer 4

i stop over here:S
\[\frac{ 4-x }{ (x-4)(x+4) }\]

Answer 5

\(\large \frac{ 4-x }{ (x-4)(x+4) }=\frac{ -1(x-4) }{ (x-4)(x+4) } =\frac{ -1\cancel{(x-4)} }{\cancel{ (x-4)}(x+4) } \)

Answer 6

thanks.
which means i'll probably get a zero for today's test lol