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Vectors determine the tension in each cable supporting the load
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You should post this in "Physics"
|dw:1349400461119:dw|
no, this is in my trig class
I know the answer, but I don't know how to solve it
Break it down into horizontal (Tx) and vertical (Ty) components. Where Tx=T cos(angle) Ty=T sin(angle) Tx(AB)=Tx(BC) Ty(AB)+Ty(BC)=(20000lbs)*g
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what?
No, thats not how you do it.
Yes it is... That is how to solve for Tension.
\[\sum_{}^{}F=0\]in equilibrium (no movement). In this case, forces are tensions.
Point C looks like a good origin to set up some vectors.|dw:1349405361838:dw|I like to set up my vectors from a standard positioning. Alternate interior angles combined with using supplements can get you the standard angles.
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