Question

Factor in the form of: y² + by + c and at² + bt + c.

Answer 1

What is the first step?

Answer 2

you can use the quadratic formula to find the two roots.
\[\frac{-b \pm \sqrt(b^{2} - 4ac)}{2a}\]
then use those roots to do (y-root1)(y-root2)=0

Answer 3

Whoa! I have not studied this method. Is there another way?

Answer 4

well you could factor out a y from parts of the equation
\[(y^2+by)\frac{y}{y}+c = y(y+b) + c\]

Answer 5

Ok