Question

How do you evaluate the integral e^(-0.01x-3) when the limits are 100 and 0

Answer 1

I thought it was 100(e^-1-e^-3) but it keeps telling me this is incorrect... Help please

Answer 2

u-sub with u=-0.01x-3, du=-0.01dx :
\(\large \int_0^{100} e^{-0.01x-3}dx=-0.01\int_{u(0)}^{u(100)} e^u du \)

Answer 3

I keep getting the same answer. I am not sure what I am doing wrong