if P(A) = 0.75 and P(B = 0.8) and P(A' \(\cap\) B') = 0.05 are events A and B independent?
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OpenStudy (calculusfunctions):
Two events A and B are independent events iff P(A and B) = P(A) x P(B).
OpenStudy (lgbasallote):
hmmm
OpenStudy (lgbasallote):
that's not dependent?
OpenStudy (calculusfunctions):
Nope!
OpenStudy (calculusfunctions):
In your question, P(not A) = 0.25 and the P(not B) = 0.2 and P(not A and not B) = 0.95.
P(not A) x P(not B) = 0.25 x 0.2 = 0.05 = P(not A and not B)
∴ A and B are independent events.
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OpenStudy (lgbasallote):
i thought B was independent if P(A|B) = P(A'|B)
OpenStudy (lgbasallote):
nevermind. i got it
OpenStudy (calculusfunctions):
Oh my gosh! There is something majorly wrong with my computer. I was almost finished with the explanation and it froze. I'll start over. Give me a few minutes.
OpenStudy (calculusfunctions):
OK good so I don't have to start over. You see that my explanation was right.
OpenStudy (lgbasallote):
yes except for a minor typographical error but understandable
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OpenStudy (calculusfunctions):
Good! Let me know if you change your mind and want to see the explanation.