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Mathematics 16 Online
OpenStudy (anonymous):

x-2>-5 or 5x>25

OpenStudy (lgbasallote):

first solve x - 2 > -5 do this by adding 2 to both sides. what do you get?

OpenStudy (anonymous):

-3 ?

OpenStudy (lgbasallote):

right x > -3

OpenStudy (lgbasallote):

now solve 5x > 25

OpenStudy (anonymous):

btw the said was suppose to be " greater than equal to"

OpenStudy (lgbasallote):

which one?

OpenStudy (anonymous):

so i just wrote greater than

Parth (parthkohli):

Doesn't matter.

Parth (parthkohli):

Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x - 2=-5\) and \(5x = 25\).

OpenStudy (lgbasallote):

\[x - 2 \ge -5 \; \text{or} \; 5x \ge 25\] ??

OpenStudy (anonymous):

Yes that correct except the first one is the the greater than symbol

OpenStudy (lgbasallote):

oh so \[x - 2 > -5 ~\text{or} ~ 5x \ge 25\]

OpenStudy (anonymous):

Yess

OpenStudy (lgbasallote):

so anyway \[5x \ge 25\] do you know how to solve for x?

OpenStudy (anonymous):

x=5 ?

OpenStudy (lgbasallote):

x \(\ge \) 5 the symbols matter

OpenStudy (lgbasallote):

so since x - 2 > -5 is x > -3 and 5x \(\ge\) 25 is x\(\ge\) 5 your answer would be x > -3 or x\(\ge\) 5

OpenStudy (lgbasallote):

@ParthKohli or is different from and

OpenStudy (anonymous):

but when it comes to graphing x>-3 is not included

OpenStudy (lgbasallote):

if you mean open circle..yes

OpenStudy (anonymous):

yeah i mean open circle , greater than is always included

OpenStudy (lgbasallote):

greater than is always included?

OpenStudy (anonymous):

lol nvm i cant explain it here :P

OpenStudy (lgbasallote):

i notice

OpenStudy (anonymous):

Okay guys one more question

OpenStudy (lgbasallote):

shoot

OpenStudy (anonymous):

excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....

OpenStudy (anonymous):

hahah thats exactly what i meant ^

OpenStudy (anonymous):

sorry @lgbasallote if I interrupted you..you can carry on with your client..

OpenStudy (anonymous):

l3xl +8>5

OpenStudy (lgbasallote):

first of all, subtract 8 from both sides

OpenStudy (anonymous):

yeah so its 5-8=-3

OpenStudy (lgbasallote):

right |3x| > -3

OpenStudy (anonymous):

so absolute value of 3x=-3 ?

OpenStudy (lgbasallote):

again. remember that signs matter. > is different from =

OpenStudy (anonymous):

yeah sorry

OpenStudy (lgbasallote):

you'll see the importance in the next step

OpenStudy (lgbasallote):

since |3x| > -3 you turn this into two equations 3x > -3 and 3x < 3 now solve for x in each one

OpenStudy (anonymous):

6 and 1 ?

OpenStudy (lgbasallote):

hmm first solve 3x > -3 divide both sides by 3

OpenStudy (anonymous):

-1

OpenStudy (anonymous):

x=-1 or x=1 ?

OpenStudy (lgbasallote):

...signs...

OpenStudy (lgbasallote):

it's not equal signs...

OpenStudy (anonymous):

sign

OpenStudy (anonymous):

nvm then

OpenStudy (lgbasallote):

it should be x>-1 and x<1 signs are very important

OpenStudy (anonymous):

Alright im done , thank you guys so much . you really helped me

Parth (parthkohli):

@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge -3\)

OpenStudy (lgbasallote):

in this case yes it is. but the fact remains that or is different from and

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