Mathematics
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OpenStudy (anonymous):
x-2>-5 or 5x>25
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OpenStudy (lgbasallote):
first solve x - 2 > -5
do this by adding 2 to both sides. what do you get?
OpenStudy (anonymous):
-3 ?
OpenStudy (lgbasallote):
right x > -3
OpenStudy (lgbasallote):
now solve 5x > 25
OpenStudy (anonymous):
btw the said was suppose to be " greater than equal to"
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OpenStudy (lgbasallote):
which one?
OpenStudy (anonymous):
so i just wrote greater than
Parth (parthkohli):
Doesn't matter.
Parth (parthkohli):
Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x - 2=-5\) and \(5x = 25\).
OpenStudy (lgbasallote):
\[x - 2 \ge -5 \; \text{or} \; 5x \ge 25\]
??
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OpenStudy (anonymous):
Yes that correct except the first one is the the greater than symbol
OpenStudy (lgbasallote):
oh so \[x - 2 > -5 ~\text{or} ~ 5x \ge 25\]
OpenStudy (anonymous):
Yess
OpenStudy (lgbasallote):
so anyway \[5x \ge 25\]
do you know how to solve for x?
OpenStudy (anonymous):
x=5 ?
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OpenStudy (lgbasallote):
x \(\ge \) 5
the symbols matter
OpenStudy (lgbasallote):
so since x - 2 > -5 is x > -3
and 5x \(\ge\) 25 is x\(\ge\) 5
your answer would be x > -3 or x\(\ge\) 5
OpenStudy (lgbasallote):
@ParthKohli or is different from and
OpenStudy (anonymous):
but when it comes to graphing x>-3 is not included
OpenStudy (lgbasallote):
if you mean open circle..yes
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OpenStudy (anonymous):
yeah i mean open circle , greater than is always included
OpenStudy (lgbasallote):
greater than is always included?
OpenStudy (anonymous):
lol nvm i cant explain it here :P
OpenStudy (lgbasallote):
i notice
OpenStudy (anonymous):
Okay guys one more question
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OpenStudy (lgbasallote):
shoot
OpenStudy (anonymous):
excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....
OpenStudy (anonymous):
hahah thats exactly what i meant ^
OpenStudy (anonymous):
sorry @lgbasallote if I interrupted you..you can carry on with your client..
OpenStudy (anonymous):
l3xl +8>5
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OpenStudy (lgbasallote):
first of all, subtract 8 from both sides
OpenStudy (anonymous):
yeah so its 5-8=-3
OpenStudy (lgbasallote):
right
|3x| > -3
OpenStudy (anonymous):
so absolute value of 3x=-3 ?
OpenStudy (lgbasallote):
again. remember that signs matter. > is different from =
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OpenStudy (anonymous):
yeah sorry
OpenStudy (lgbasallote):
you'll see the importance in the next step
OpenStudy (lgbasallote):
since |3x| > -3 you turn this into two equations
3x > -3 and 3x < 3
now solve for x in each one
OpenStudy (anonymous):
6 and 1 ?
OpenStudy (lgbasallote):
hmm
first solve 3x > -3
divide both sides by 3
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OpenStudy (anonymous):
-1
OpenStudy (anonymous):
x=-1 or x=1 ?
OpenStudy (lgbasallote):
...signs...
OpenStudy (lgbasallote):
it's not equal signs...
OpenStudy (anonymous):
sign
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OpenStudy (anonymous):
nvm then
OpenStudy (lgbasallote):
it should be x>-1 and x<1 signs are very important
OpenStudy (anonymous):
Alright im done , thank you guys so much . you really helped me
Parth (parthkohli):
@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge -3\)
OpenStudy (lgbasallote):
in this case yes it is. but the fact remains that or is different from and