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Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).
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the product of slopes of perpendicular lines is -1 So you know the slope of given line, find the slope of its perpendicular line and use y-y1 = m(x-x1)
Hint: m1*m2 = -1
can you work this one out I work better when I have examples and I have more questions I have to do. Please
slope of give line = -a/b i.e m=2/3 therefore slope of perpndicular on the given line is = -3/2 passing through (-8,2). Now apply slope-point form.
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