Question

f(x) = 2x^2 - 16x +27
How do I find the axis?

Answer 1

what you mean by axis???

Answer 2

The axis of symmetry.

Answer 3

You mean the vertex?

Answer 4

find the \(y\)-coordinate in the vertex.

Answer 5

x-coordinate**

Answer 6

The original question was "Find the axis of symmetry of the graph of the function.

f(x) = 2x^2 - 16x + 27"

Answer 7

Complete the square or use the first term of the quadratic formula.

Answer 8

use formula x=-b/(2a)

Answer 9

I thought that was how you would find the vertex.

Answer 10

The vertex is on the axis of symmetry, so the process is related.

Answer 11

Finding the axis of symmetry is a step along the way to finding the vertex.

Answer 12

Well the vertex is (4,-5).

Answer 13

Looks like you're all set then. Good work!

Answer 14

Wait, how does that give me the axis of symmetry?

Answer 15

What is the X-coordinate of the vertex?

Answer 16

4

Answer 17

So, \(\rm x = 4\) is your vertex!

Answer 18

Given
\[y=ax^2+bx+c = a(x-h)^2+k\]
The axis of symmetry is x=h.

Answer 19

axis of symmetry**

Answer 20

Oh I see. Thanks, guys!