Question

PLEASE give me guidance?

What is the value of y in the solution to the following system of equations?5x - 3y = -32x - 6y = -6

Answers:



-1

0

1

2

Answer 1

see we get y=37/21 according to your equations

Answer 2

Correct

Answer 3

You did something wrong with the question..check it

Answer 4

5x - 3y = -32x - 6y = -6

Answer 5

You break it in two?

Answer 6

well, if you are right with your question, then y=37/21 but you do not have it in your answer choices?

Answer 7

yes, break it into two as 5x-3y= -6 and -32x-6y = -6

Answer 8

No, it has to be one of the answers I provided

Answer 9

(The answer I got was -1)

Answer 10

show how it is -1

Answer 11

Thanks dude for your support @bhaskarbabu

Answer 12

Okay

Answer 13

I see how you would, but you have to break it into one digit

Answer 14

:)

Answer 15

Do it carefully, its 37/21

Answer 16

Heh, rushed through that, yes y=37/21.

Answer 17

1.7619047619

Answer 18

Are you sure you aren't missing a piece of one of the equations?

Answer 19

Does 5x-37 actually equal something else?

Answer 20

yes,that's it... 1.762

Answer 21

My apologies, but that's what it was written as

Answer 22

Would it be a positive 1 instead...?

Answer 23

It is more reasonable to be positive 2

Answer 24

Not an option

Answer 25

What about this one?

Use the substitution method to solve the following system of equations.x + y = 32x + 2y = 10

Answer 26

x= -1 and y = 21

Answer 27

It's either 1 or -1

Answer 28

So it's negative one?!!! I WAS RIGHT!!!!!!!!!!!!!!!!

Answer 29

/8, Assuming the second equation, -32x-6y=-6 is correct, and the solution for y must be /16, -in the set, {-1, 0, 1, 2}, then solving for possible values of x:
\[x=\frac{3}{16}-\frac{3}{16}[-1, 0, 1, 2] = [\frac{3}{8}, \frac{3}{16}, 0, \frac{-3}{16}]\]

And your first equation might actually be 5x-3y=[39/16, 15/16, -3, -111/16]

Answer 30

Thank you for breaking it down for me, @CliffSedge

Answer 31

I just noticed your picture is of you or someone on a cliff and your username has the word "cliff" in it haha

Answer 32

So, all in all, -1 was correct?

Answer 33

In other words, in the more-than-likely event that the first equation is actually 5x-3y=-3, the solution to the system would be (0,1)

Answer 34

A positive 1?

Answer 35

How did you get zero, sir?

Answer 36

He/she corrected the equations you gave at the beginning of this question thread...then you get x=0 and y=1

Answer 37

Thank you, my sincerest apologies....@AbhimanyuPudi

Answer 38

The possible answer choices for y that you posted were {-1, 0, 1, 2}.
I put all of those into the second equation and solved for x and got {3/8, 3/16, 0, -3/16}
Putting all those solutions into the first equation, I got other possibilities for what
5x-3y could equal. All the other coefficients were integers, so I induced that out of that set, that -3 was most likely. In that case, the solution would be (0,1).

Answer 39

Thank you both @AbhimanyuPudi and @CliffSedge

Answer 40

OHHHHHHH!!!!

Answer 41

Thank you

Answer 42

It's a weak conjecture, but seems more likely than the solution being 37/21.

Answer 43

Agreed

Answer 44

a strong assumption

Answer 45

If the correct answer isn't in the list of options, then either the question or the list of possible answers is wrong. It's hard to tell which; there are so many possibilities.

Answer 46

I have a strong theory here @InsanelyChaotic @AbhimanyuPudi

5x-3y=-32x-6y=-6, like the other question is a case of not putting a space or line between
5x-3y=-3
2x-6y=-6

If you solve that system, you'll see that (0,1) is correct.

Answer 47

I'm sorry, you are all idiots, and especially @InsanelyChaotic

yes, it was two separate equations, and was listed as two separate equations on two separate lines of text in the UNIT TEST!!!

Answer 48

Thank you for figuring that out @CliffSedge
*medal!*