Question

Solve the equations:
x-y-5=0,
x^2+2xy+y^2=9.
.
.
.
ANSWER = {(4,-1),(1,-4)}

Answer 1

HELP...

Answer 2

opinion from this ???

Answer 3

i want to solve this by substitution

Answer 4

there is a system of equations

Answer 5

so if you wann to solve it by substitution method what you need to do for ?

Answer 6

how will i do this by substitution i dont understand the equations... thats the point of asking

Answer 7

hint: if you have y = something, then you can plug that in for y in the other equation.

Answer 8

like y=x-5 right??

Answer 9

not is necessary so if you know how you need ,how you can substitute the y value or x value from one equation in place of y or x inside second equation

ok ?

Answer 10

note if i had x+y = 3, and x+2y = 12
solve for y in the first equation
y = 3-x
plug this in for y in the second equation
x+2(3-x) = 12
x+6 - 2x = 12
-x = 6
x = -6

now i plug this into either equation and solve for y

Answer 11

koli there you was right

continue it

Answer 12

y=x-5 ??

Answer 13

yes is right sure

Answer 14

what should i do with this put it in second equation?

Answer 15

yes

Answer 16

yes

Answer 17

ok wait

Answer 18

just you need to make the calcule

Answer 19

x^2+2x^2-10x+x^2-10x+25=0 by substituting y

Answer 20

4x^2-20x+25=0 by simplifying further

Answer 21

yes and continue it

Answer 22

(x-5)(4x-5) by factorizing right??

Answer 23

x=5 and x=5/4

Answer 24

so if you have maked right,correct these calcules than is right sure

hope so much that you have understood it all

Answer 25

not yet

Answer 26

yes because now if you have the x values you need to calcule again the y values

ok ?

Answer 27

I thought your x values were 4 and 1

Answer 28

not mine x values that is the book's answer

Answer 29

so if you know that x=y+5 so than y= ?

Answer 30

it means i am doing wrong?

Answer 31

koli you dont wann writing here your calcules for can being checked ?

Answer 32

what?

Answer 33

so if x=y+5 than the second equation will be

(y+5)^2 +2(y+5)y +y^2 =9 so can you continue it ?

Answer 34

he said show us your work

Answer 35

yes

Answer 36

the book is wrong it seems because this will factor into c(x+b)(x+a) = 0
so both our x's will be positive

Answer 37

err negative*

Answer 38

koli let's go please now here

Answer 39

i did a mistake

Answer 40

show your work to him:)

Answer 41

i forgot about 9 in eqn 2 opps wait i am solving again

Answer 42

(y+5)^2 +2(y+5)y +y^2 =9 so can you continue it ?

Answer 43

y^2 +10y +25 +2y^2 +10y +y^2 =9

continue it please

Answer 44

4y^2+20y+16=0

Answer 45

yes and continue it

Answer 46

come on ,please !!!

this is easy

Answer 47

wait i am doing

Answer 48

write it here please

Answer 49

y=-1 and y=-4

Answer 50

so divide both sides by 4 and will get ???

Answer 51

i did it by quadratic formula

Answer 52

and i am substituting the values of y in x=y+5

Answer 53

4y^2+20y+16=0 /4
y^2 +5y +4 =0 factoriz it and will get
(y+4)(y+1)=0

right ?

Answer 54

ANSWER = {(4,-1),(1,-4)} DID IT!!

Answer 55

thanks for helping me out

Answer 56

you have got it right understood it all ?

Answer 57

there is a question a very tuff one not like this question i have already asked it before but nobody could answer it, i waited for hours and nobody helped me out i am posting the question please can u help

Answer 58

but firstly this equation you have understood it all right sure ?

Answer 59

yeah i got it

Answer 60

ok so than i like help you so if i will can to do it

what is your question ?