Need help with finding four numbers! (Problem in comments)

Question

anonymous · Answer

Suppose you have four numbers (call them a,b,c,d). They have the following characteristics:
a is a perfect cube
b is a perfect square
c is divisible by 10
d is ONLY divisible by 5

They are also related in the following ways:
$$c-a=4+b$$
$$d/c = (a-(d-51)/a-(c-69))$$
$$bc-ad = 2165$$
$$-5(d-3a) = 80$$

What is a, b, c, and d?

anonymous · Answer

Oh, and just so it doesn't cause any confusion, the second equation can also be written as:
$$d/c = (a-(d-51)\div(a-(c-69))$$

anonymous · Answer

well i'm doing some calculations...but i think one thing i know is that d is 5?

anonymous · Answer

how did you get d=5, joshi? I would just like to know how to start dealing with all of these.

anonymous · Answer

oh wait never mind what i said about d.
from c-a=4+b, i got c=4+b+a 
and i cross multiplied the second equation. and substituted c for 4+b+a
that's what i have until now

anonymous · Answer

Bahh...I'm just gonna give up on this stupid problem. Thanks for your help, though.

anonymous · Answer

aw nooo well do you know the actual answer though? i'm going to finish this anyway, you're welcome