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What are the coordinates of the terminal point determined by t = 20pi/3
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You'll be going counterclockwise around the circle more than once. Each time you make a complete revolution you subtract 2pi (6pi/3) from the total. What remainder do you get?
so 20pi/3-6pi/3 ?
would it be in the second quadrant or fourth?
20pi/3-6pi/3 is what's left over after the first revolution. Go araound again.
would it be 1/2,-sqrt3/2?
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No. How many full sets of 6pi/3 are there in 20pi/3?
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