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OpenStudy (anonymous):
What are the coordinates of the terminal point determined by t = 20pi/3
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OpenStudy (noelgreco):
You'll be going counterclockwise around the circle more than once. Each time you make a complete revolution you subtract 2pi (6pi/3) from the total. What remainder do you get?
OpenStudy (anonymous):
so 20pi/3-6pi/3 ?
OpenStudy (anonymous):
would it be in the second quadrant or fourth?
OpenStudy (noelgreco):
20pi/3-6pi/3 is what's left over after the first revolution. Go araound again.
OpenStudy (anonymous):
would it be 1/2,-sqrt3/2?
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OpenStudy (noelgreco):
No. How many full sets of 6pi/3 are there in 20pi/3?
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