Question

factor the trinomial completely. -n^2+28n-27

Answer 1

-n^2+28n-27

-(n^2-28n+27)

Now find two numbers that multiply to 27 and add to -28. What are these two numbers?

Answer 2

there are no numbers that will add up to that

Answer 3

how about -27 and -1?

Answer 4

-27 plus -1 = -28

Answer 5

I tried that and it said it was wrong

Answer 6

and it's not prime either

Answer 7

so n^2-28n+27 factors to (n-27)(n-1)

Answer 8

which means that

-(n^2-28n+27)

becomes

-(n-27)(n-1)

Answer 9

So

-n^2+28n-27

completely factors to

-(n-27)(n-1)

Answer 10

I tried that and it said that it was wrong

Answer 11

even with the negative out front?

Answer 12

if

-(n-27)(n-1)

doesn't work, then try

-1(n-27)(n-1)

Answer 13

(n - 27)(-n + 1) Will that work?