Question

Help please.

Answer 1

x-vertex of y=ax^2+bx+c is given by
-b/(2a)

Answer 2

can you tell what is the x vertex now ?

Answer 3

I really don't understand this :/
I don't know ...

Answer 4

so as i wrote x-vertex of y=ax^2+bx+c is given by
-b/(2a)

in our case y = -3x^2 -x + 8
so a = -3 , b = -1 , c = 8

so x vertex is given by

-(-1)/(2*(-3)) = 1 / (-6) = -1/6

Answer 5

in order to find the y of the vertex you have to plug x=-(1/6) into the equation
can you do it ?

Answer 6

Okay I get the x vertex now but I don't know what to do next.

Answer 7

in order to find the y of the vertex you have to plug x=-(1/6) into the equation
can you do it ?

Answer 8

what is y(-1/6) ?

Answer 9

are you trying ?
y(-1/6) = -3 * (-(1/6))^2 - (-(1/6)) + 8 = ?