Among 60 automobile repair parts are loaded on a truck in San Franscisco, 45 are destined for Seattle and 15 for Vancouver. If two of the parts are unloaded in Portland by mistake and the "selection" is random, what is the probability that one should have gone to Vancouver and one to Seattle?
I'm unsure of what to do here.
Find the probability that: - a part destined for Vancouver will get unloaded. - a part destined for Seattle will get unloaded. Then, find the probability that one Vancouver part *and* one Seattle part will get unloaded.
I understand that, but I'm unsure of how ,y book is getting their answer of 1/243. The probability that a part destined for Seattle will get unloaded is \[\frac{ 44 }{ 59 }\] and the one for Vancouver is \[\frac{ 14 }{ 58 }\]. When I add those together I don't get 1/243.
".y" should be "my"
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