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Mathematics 9 Online
OpenStudy (anonymous):

I have no idea how to start but I did question a! 4a) The median of four scores is 12. If two of the scores are 7 and 15, write possible values for the other two scores (I wrote 12,12; 11, 13; 10, 14; 9, 15) 4b) Four scores have a range of 10 and their median is 13. Two of the scores are 7 and 9. What are the other two scores 4c) The man of four scores is 20. If one score is 18, what are the possible values of the other three scores?

OpenStudy (kropot72):

Your solution to 4a) is correct :) 4b) Choose 7 as the first score and 7 + 10 = 17 as the last. So the sequence could be: 7, 9, x, 17 To give a median equal to 13, (9 + x)/2 = 13. Now solve for x.

OpenStudy (anonymous):

@kropot72 can you explain why you did that? I am getting confused by the 'range of 10' part

OpenStudy (kropot72):

When the numbers in a distribution are ranked from lowest to highest, the range is the difference between the highest and the lowest numbers. Therefore to give a range of 10, I added 10 to my choice of 7 for the lowest number making the highest number 17. Do you follow?

OpenStudy (anonymous):

Yes I get it now :)

OpenStudy (kropot72):

Good work :)

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