Question

Solve the equation (x-1/x)^2+3(x+1/x)=0
.
.
.
ANSWER = {1±√(3i)/2,-2±√(3)}

Answer 1

wait i am explaining it all just wait

Answer 2

\[(x-\frac{ 1 }{ x })^2+3(x +\frac{ 1 }{ x })=0\]

Answer 3

this is the question

Answer 4

and this is the answer

Answer 5

write (x-1/x)^2 as (x+1/x)^2 -4
and put y= x+1/x

Answer 6

\[\frac{ 1±\sqrt{3i}}{ 2 },-2±\sqrt{3}\]

Answer 7

this should e the answer

Answer 8

do you want us to show the steps?

Answer 9

nope just want the ideason how to solve it

Answer 10

write (x-1/x)^2 as (x+1/x)^2 -4
and put y= x+1/x
could u take i from here ?
u get a quadratic in y

Answer 11

its your choice whether u show the steps or not

Answer 12

y^2+3y-4=0
solve this

Answer 13

I think @hartnn gave you the best way.

Answer 14

\[(\frac{x^2-1}{x^2})^2+3(\frac{x^2+1}{x^2})\]

Answer 15

ok i am solving the quadratic

Answer 16

@MrMoose no squares inside brackets of the question

Answer 17

\[\frac{(x^2-1)^2+3(x^2-1)^2}{x^4}\]

Answer 18

\[u = x^2\]
\[(u-1)^2+3(u+1)^2 = 0\]

Answer 19

\[4u^2+4u+4=0\]

Answer 20

\[4(x^4+x^2+1) = 0\]

Answer 21

\[x^4+x^2+1\]
obviously has the factors w and w^2, where they are the 3rd roots of unity

Answer 22

@hartnn i've solved the quadratic and its coming y=1 and y=-4 whats next

Answer 23

@MrMoose there is no x^2 in the question how did u get x^2

Answer 24

now x+1/x = 1 or x+1/x = -4
so u get
x^2+1=x or x^2+1 = -4x
now solve these 2 quadratics.
preferably using formula

Answer 25

by getting a common denominator
\[(x-\frac{1}{x}) = (\frac{x^2-1}{x}) \]

Answer 26

the denominator u=is also x^2 as u mentioned above @MrMoose

Answer 27

the denominator doesn't matter

Answer 28

if the numerator is 0, the whole thing is 0

Answer 29

@hartnn the first quadratic solved and it is matching the first answer now checking second one

Answer 30

done thanks @hartnn

Answer 31

welcomes :)

Answer 32

@hartnn goku charging his spirit bomb?

Answer 33

yeah ! give him your energy :P

Answer 34

given :)