Mathematics
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OpenStudy (anonymous):
Solve the equation (eqn coming soon)
.
.
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ANSWER = {1/4,4}
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OpenStudy (anonymous):
\[(\frac{ x+2 }{ x-1 })^2+(\frac{ x+2 }{ x-1 })-6=0\]
hartnn (hartnn):
let y= x+2 / x-1
OpenStudy (anonymous):
any hints?? how should i start
OpenStudy (anonymous):
ok
hartnn (hartnn):
u get quadratic in y
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OpenStudy (anonymous):
ok i am solving
OpenStudy (anonymous):
woah! it was so easy the look of the question was confusing
OpenStudy (anonymous):
not really!
hartnn (hartnn):
y= ?
OpenStudy (anonymous):
\[y=\frac{ -1\pm \sqrt{-23} }{ 2 }\]
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OpenStudy (anonymous):
now what?
hartnn (hartnn):
i m getting 2,-3
OpenStudy (anonymous):
Me too.
OpenStudy (anonymous):
;( how?
OpenStudy (anonymous):
You might have done a mistake..
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OpenStudy (anonymous):
y^2+y-6=0 is the equation right??
hartnn (hartnn):
yes
hartnn (hartnn):
b^2-4ac = ?
hartnn (hartnn):
1-(-24) = ?
OpenStudy (anonymous):
oh c was -6 i did it +6
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OpenStudy (anonymous):
now i have to put the values of y right??
hartnn (hartnn):
yes
x+2 / x-1 = 2
x+2 / x-1 =-3
cross multiply
OpenStudy (anonymous):
first one x=4
hartnn (hartnn):
:)
OpenStudy (anonymous):
I got only one and it's x = 4
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OpenStudy (anonymous):
the second is x=1/4
hartnn (hartnn):
\(\huge \color{red}{\checkmark}\)
OpenStudy (anonymous):
@Miyuru we have to put y 2 times as we got it 2 "2 and 3"
OpenStudy (anonymous):
oops 2 and -3
OpenStudy (anonymous):
Ohh yeah I forgot... :D
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OpenStudy (anonymous):
Did you checked your answer in the first equation... :)