Question

If the graphs of 2y +x +3 =0 and 3y +ax +2 =0 are perpendicular, find the value of “a”.

Answer 1

If the lines are perpendicular their product of slopes = -1 ie m1*m2 = -1

Answer 2

1 st find the slope of two equation

Answer 3

@Yahoo! then just multiply the slope of one line by the opposite reciprocal and solve for a, correct?

Answer 4

2y=-x-3
y=(-1/2)x-3

using equation y=mx+c
m1=-1/2

3y=-ax-2
y=(-a/3)x-2

using again y=mx+c
m2=-a/3

for perpendicular lines m1xm2=-1

(-1/2)x(-a/3)= -1
a/6=-1
a=-6 is your answer

Answer 5

Whenever you get there kind of questions remember that product of slopes of two perpendicular lines in always -1