Write this equation in slope-intercept form, and then find the slope and y-intercept. -y=3x
slope-intercept form = y=mx+c
Where m = slope c=y intercept
y=-3x+0 Slope =-3 intercept =0
-y=3x Multiply by -1 y = -3x + 0 y inetrcept = 0 slop = -3
y=mx+b m is the slope, b is the y-intercept -y=3x → y=-3x + 0 slope, m, is -3. y-intercept, b, is 0 In order to find the x-intercept, you must plug in 0 for y 0=-3x → x=0/-3 → x=0
So how exactly did you get to the slope and y-intercept?
I'm confused..
This form is called slope-intercept form because just by looking at the equation you can immediately tell what the slope and the y-intercept are m= slope b= y-intercept (another way to find the y-intercept is to plug in 0 for x)
Okay...So how did you get -3?
-y=3x You can divide both sides by - -y/-= y 3x/- = -3x y=-3x
Oh...Thanks! :D
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