Question

Find the points of discontinuity. f(x)= cotx

Answer 1

differentiate cot x
f'(x)=- (cosecx)^2
cotx becomes undefined at x=0

Answer 2

\(\large f(x)=cotx=\frac{cosx}{sinx} \)

points of discontinuity occurs where the denominator is zero so solve: sinx = 0
to find them...

Answer 3

ok thanks I understand it

Answer 4

@katluu point of discontinuity would occur at x=0 since sin 0 =0