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When f(x) is divided by ( x-3 ), the remainder is 2. So if i divided 2[f(x)]^2-3 by ( x-3 ) what is the remainder?
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because f(3)=2, then f(3)+5=2+5=7 i sure, u understand what i mean :)
haha, yes thank you
welcome :)
@RadEn I really like your idea, but I think you are missing the part where you are dividing one into another. But its true that if you take the remainder and then add 5 to it you get 7. Works the same with mine.
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ok, thank u for remember it
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