Question

Need some help with these problems :/ 1. Your club is baking vanilla and chocolate cakes for a bake sale. They need at most 15 cakes. You cannot have more than 11 chocolate cakes. Write and graph a system of inequalities to model this system. Let x = the number of vanilla cakes. Let y = the number of chocolate cakes. 2.Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115732-AM-38496864.png 3. Solve the system of inequalities by graphing. https://www.connexus.com/content/media/642225-162012-115514-AM-349314999.png

Answer 1

Help on any one of them would be appreciated :/

Answer 2

Hey Satellite (:

Answer 3

hi

Answer 4

Hahah yay, Satellite to the rescue.

Answer 5

the second two wont open
the first one is going to be
\[x+y\leq 15\]
\[y\leq 11\]

Answer 6

Hm thats odd :/ One sec I'll copy em down by hand.

Answer 7

picture looks like this
http://www.wolframalpha.com/input/?i=x%2By%3C%3D15%2Cy%3C%3D11

Answer 8

Thanks for that ^-^

Answer 9

yw

Answer 10

y is Less than or equal to -4x-2 , y > 3x-2 Is the first problem.

Answer 11

and y is greater than or equal to 3 , y> lx+1l Was the 2nd one, haha those are absolute value signs sorta btw x.x

Answer 12

LOL XD

Answer 13

that's so helpful..

Answer 14

These questions are junk :P

Answer 15

here is a better picture
the idea is to graph the two lines and then shade in the appropriate region
http://www.wolframalpha.com/input/?i=y%3C+-4x-2+%2C+y+%3E+3x-2

Answer 16

I hate solving junk by graphing so much x.x I'd rather like chop off a finger Dx

Answer 17

you have to graph \(y=-4x-2\)a line with slope \(-4\) and \(y\) intercept \(-2\) then graph \(y=3x-2\) a line with slope 3 and y intercept also \(-2\)

Answer 18

Yeah I get that I just suck at actually figuring it out :/

Answer 19

what region to graph, or how to graph the lines?

Answer 20

well haha I'll give em my best educated guess x)

Answer 21

How to graph them :P

Answer 22

i sent you a link with the graph of the second one

Answer 23

oh get some graph paper and plot two points for each line
for example, for \(y=-4x-2\)you know it crosses the \(y\) axis at \((0,-2)\) and if \(x=2\) you get \(-10\) so \((2,-10)\) is on the graph, or, go over one, down 4
connect the dots la la la la la
repeat for second line
it is tedious but you can do it

Answer 24

or type them in to wolfram and let the machine do it
there is really no shortcut, you just have to graph the lines

Answer 25

lol yeah ! that's true, I think I'll be alright on the test on it. but I do need to find my pesky graph paper :/ Keeps hiding on me.

Answer 26

I'm probly gonna start using that site more too haha

Answer 27

as for \(y=|x+1|\) it looks like a V sitting at \((-1,0)\)