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f(x)=3x-1 and g(x)=x^2+4. Find f(g(6))
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Plug in 6 into g(6) and then plug in the answer of g(6) into f(x)
\[f(g(x))=f(x^2+4)=3(x^2+4)-1=\]
I keeep getting the answer wrong.
what are you getting?
g(6) = (6)^2 + 4 = 36 + 4 = 40. f(40) = 3(40) - 1 = 120 - 1 = 119
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how do i type that answer
I am doing practice questions on the computer and no matter how i write it it says its wrong?@
\[f(g(6))=f(6^2+4)=3(6^2+4)-1=\]
f(g(6)) = (fog)(6) @UnkleRhaukus and @vintageballad are right
i didnt know if there was another way to write the answer
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did you get a single value when simplified ?
now, u knowed that :)
(fog)?
yes :0)
\[(f\circ g)(x)=f(g(x))\]
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I think I am confusing myself
look at vintageballad's work
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