Question

Can I get some help with Trig identities?

Answer 1

solve the following in the interval [0,2pi)
\[\tan x + \sqrt{3} = \sec x\]

Answer 2

what is another way to write tan and sec?

Answer 3

tan = sin/cos and sec =1/cos

Answer 4

I used that, but as i got further along I got stuck. Should I set it up as a quadratic?

Answer 5

\[\frac{ \sin }{ \cos}x+\sqrt{3}=\frac{ 1 }{ \cos }x\]

Answer 6

i got to
\[\sin x - \cos x +\sqrt{3}\cos x = 0\]
am i on the right track?

Answer 7

\[\sin x-1+\sqrt{3}cosx=0\]