Question

please help
2x+4 over x-2 divided by 4x over x^2-4

Answer 1

Wow, that's a problem. Ok, I'll do my best to explain.
Basically, when dividing a fraction by a fraction it turns into a multiplication problem. You take the INVERSE of the bottom fraction and multiply it by the top fraction. So, here's how it'll look
2x+4 over x-2 MULTIPLIED by x^2 - 4
So you multiply across.
From this point, you simplify your answer. I'd tell you how but I'm not THAT great with fractions so I don't wanna mess you up. If you want, I can still show you step by step what I did but I'm unsure of myself. I know for sure what I told you is correct though.

Answer 2

ok please

Answer 3

Ok
so you would set it up like this
(2x+4)(x^2-4) ALL OVER (x-2)(4x)
So you multiply the top separately from the bottom.
2x^2 - 8x + 4x^2 - 16 ALL OVER 4x^2 - 8x
You combine like terms
6x^2 - 8x -16 ALL OVER 4x^2 - 8x
Now this should start to look like a quadratic formula so obviously you solve it from here. Do you need help solving the quadractics? And if you do, tell me the method you use to solve them.

Answer 4

isnt it 2x^3??

Answer 5

Where? As the overall problem answer or somewhere in the equation?

Answer 6

because when you multiply 2x by x^2 it gives you 2x^3

Answer 7

in the equation

Answer 8

hey kmayb, i got \[2^{3} \over 4x-2\]

Answer 9

Yes,sorry, I didn't see that I put that in the equation. But anyway, knowing that, do you know how to solve the problem from there?

Answer 10

thats the problem i dont know how to answer it

Answer 11

musieu aller

Answer 12

giet manman'l li te sot

Answer 13

bump it

Answer 14

pitot ou mender on lot question anko

Answer 15

i can't

Answer 16

close this one