f(x)= { (2x+p)/k for x=1,2,3,4,5
0 for all other values of x
given that f(2) = 1/7
find p and k
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
put x=0 in f(x) what u get ?
OpenStudy (anonymous):
zero...?
hartnn (hartnn):
yes, as f(0) = 0, u directly get p first
OpenStudy (anonymous):
p=0?
hartnn (hartnn):
f(x) =0 for any other value of x, so it will be 0 for x=0
yes! p=0 is correct :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
now put x=2 in f(x)
OpenStudy (anonymous):
but the answer says p=1
hartnn (hartnn):
@sauravshakya could u verify the working ?
hartnn (hartnn):
is k = 28 given ?
OpenStudy (anonymous):
no~ k=35 >.<
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
i wonder what mistake i did...
OpenStudy (anonymous):
f(6)=0
(2*6+p)/k=0
p=-12
OpenStudy (anonymous):
So, I think f(0)=0 cannot be done.
hartnn (hartnn):
lol. so u cannot find p like that way
OpenStudy (anonymous):
f(2)=1/7
(2*2+p)/k=1/7
28+7p=k
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
thats the only equation....
OpenStudy (anonymous):
Yes.
hartnn (hartnn):
anything else is given ? @Kystal
OpenStudy (anonymous):
I think we are suppose to find the range of values of p and k
OpenStudy (anonymous):
The probability distribution function, f(x), for the discrete random variable X is given by the rule:
f(x)= { (2x+p)/k for x=1,2,3,4,5
0 for all other values of x
given that f(2) = 1/7
find p and k
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
ohh!!
hartnn (hartnn):
now it can be solved
OpenStudy (anonymous):
THEN,
f(1)+f(2)+f(3)+f(4)+f(5)=1
hartnn (hartnn):
^^ thats the 2nd equation
OpenStudy (anonymous):
Yep that will give another equation and u need to solve those two equations to find p and k
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
can u find 2nd equation ?
OpenStudy (anonymous):
erm...30p/k=1 ?
hartnn (hartnn):
nopes,
did u put 1,2,3,4,5 in place of x ?
and equated to 1 ?
OpenStudy (anonymous):
yea...?
hartnn (hartnn):
(2+p+4+p+6+p+8+p+10+p)/k = 1
so the equation becomes ?
Still Need Help?
Join the QuestionCove community and study together with friends!