Question

Is there any relation between ln(-1) and sqr root(-1)

Answer 1

ln(-1) = i\(\pi \)

Answer 2

from e^{i\(\pi\)} = -1

Answer 3

Oh...... ya

Answer 4

Let i^i = e^x ->

i ln i = x

i ln (sqrt(-1)) = x

i/2 ln -1 = x but since ln -1 = ipi

x = -pi/2

Answer 5

WELL THANX GUYS

Answer 6

So,

Answer 7

That is also TRUE?

Answer 8

yep.

Answer 9

So, all numbers do have relation?

Answer 10

euler's relation is great!

Answer 11

agreed.