Question

y=-(x-1)^4 find x intercepts

Answer 1

I know how to get y intercepts.. and I guess in general i know how to find x intercepts. just rusty at breaking this out into a quadratic...

Answer 2

?

Answer 3

to find x-intercept, put y = 0

Answer 4

0 = -(x-1)^4
0 = x-1

1 = x

x = 1

Answer 5

hmm so u dont have to simplify?

Answer 6

already its in factored form, simplified form :)

Answer 7

so what about for y = (x-4)^3 - 2

Answer 8

i guess i am confused then what to do with the exponent

Answer 9

\[y=(x-4)^{3}-2\]

Answer 10

you wanto find x-intercept or y-intercept ?

Answer 11

2 = (x-4)^3
cube root each side?

Answer 12

x. i know how to find y.

Answer 13

yes

Answer 14

so

Answer 15

\[\sqrt[3]{2}=x-4\]

Answer 16

\[x=4\sqrt[3]{2}\] ??

Answer 17

er 4 + cube rt of 2

Answer 18

thank god ;)

Answer 19

awesome.. thanks for your help...

Answer 20

looks you've mastered these ! np :)

Answer 21

what did u do when the exp was 4 in the original question.

Answer 22

0 = -(x-1)^4
0 = x-1

1 = x

x = 1

Answer 23

0 = -(x-1)^4
0 = -1(x-1)^4

Answer 24

since -1 is NEVER equal to 0, (x-1)^4 must be equal to 0

Answer 25

so,

0 = (x-1)^4

Answer 26

the -1 outside of the parens u mean

Answer 27

yes

Answer 28

0 = (x-1)^4

take 4th root,

0 = (x-1)

Answer 29

and the 4th root of 0 is 0... i see now.

Answer 30

:)

Answer 31

lol so much easier than i thought.. i had x^4 + 96x^3 and other stuff lol. thanks again

Answer 32

those would be easy too, just we factor HCF i guess... good luck !