Question

log(10^2x - 56) - x = 0

Not sure how to tackle this question... Any pointers?

Answer 1

what's the base 10 or e

Answer 2

@bhaskarbabu Base 10.

Answer 3

entire (2x-56) is in exponent ?

Answer 4

@ganeshie8 Nope, 10^2x and -56.

Answer 5

thats why u posted this :s

Answer 6

@ganeshie8 That's why I post what?

Answer 7

nvm :)

Answer 8

start with converting log to exponent

Answer 9

log(10^2x - 56) - x = 0

10^2x - 56 = 10^x

Answer 10

and let 10^x = k, and solve the quadratic maybe

Answer 11

log(10^2x - 56) = x

10^2x - 56 = 10^x

10^2x -10^x - 56 =0
let 10^x=k
k^2-k-56 = 0
solve for k

Answer 12

@bhaskarbabu Ah, I see. Thanks!