Question

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Answer 1

idk the patterns u refer to but this polynomial is certainly factorable... b=16 and \(\large b^2=64 \) so the factorization is:

\(\large x^2-16x+64=(x-8)(x-8)=(x-8^2) \)

Answer 2

that should be b=-16 and \(\large b^2=64 \)

Answer 3

yw...