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Solve,If two numbers are chosen from (1,2,….25) what is the probability that one of the numbers is twice greater than the other number?
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hmmm... i'm not very good at these but i'll take a stab at it.... the total possible ways of taking 2 numbers out of 25 is 25 choose 2: 25 C 2 now there are 12 ways to choose those two numbers such that one number is twice the other... so my answer(guess) would be: \(\large \frac{12}{\text 25 C 2} \) ????
The total possible is 25*24 right?
25 C 2 = (25 !)/[(2!)(23!)] = (25)*(24)/[2] = 25*12
|dw:1349724363712:dw|
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