Question

identify the vertex and the y-intercept of the graph of the function y=(x-3)^2-5. Please explain how to do this!!

Answer 1

Are you in calculus or algebra?

Answer 2

Algebra.

Answer 3

Do you have a graphing calculator?

Answer 4

not yet

Answer 5

for the y intercept set x to 0. y= (0-3)^2 -5. Which will equal 4. So y=4

Answer 6

So whenever i am finding y-intercept i make x 0?

Answer 7

what about the vertex?

Answer 8

Yes give me a second on the other.

Answer 9

okay thanks a lot

Answer 10

would the vertex be (3,5)

Answer 11

The vertex is a maximum point on a graph. This graph is going to be an upward parabola.

Answer 12

Is that the graph you plotted

Answer 13

i didnt make a graph

Answer 14

I do believe it is (3,-5). Would you care to share how you did it

Answer 15

I did this y = a(x - h)^2 + k, where (h, k) is the vertex.