Find dy/dx by implicit differentation:
5+3x=sin(xy^7)

Question

Find dy/dx by implicit differentation: 
5+3x=sin(xy^7)

anonymous · Answer

what have you got so far? do you know how to differentiate implicitly?

anonymous · Answer

I don't even know how to start.. My professor has a very strong accent and I was completely lost during the lecture today.

anonymous · Answer

what is written xy power????

anonymous · Answer

$$5+3x=\sin(xy^7)$$

anonymous · Answer

ok....just wait for answer

anonymous · Answer

I don't want the answer. I want to know how to do it.

anonymous · Answer

If you want some help actually understanding implicit differentiation and not just an answer then check these out: http://www.khanacademy.org/math/calculus/differential-calculus/v/implicit-differentiation http://tutorial.math.lamar.edu/Classes/CalcI/ImplicitDIff.aspx

anonymous · Answer

thank you!

anonymous · Answer

i find Paul's Online Notes and Khan Academy to be the best at teaching things online :) goodluck :)

anonymous · Answer

5+3x=sin(xy7)
taking derivative on both sides
3=cos(xy7)(x.d/dx(y7).d/dx(y))+y)
3=cos(xy7)(x7y6.dy/dx+y)
3-ycos(xy7)=cos(xy7)(x7y6.dy/dx)
dy/dx=3-ycos(xy7)/cos(xy7)7xy6