Question

how do I find the inverse of y=(0.5)^(x+2)???

Answer 1

\[y=(0.5)^{x+2}\]
x = (0.5)^(y+2)
logx = y+2log0.5
logx/log0.5 = y+2log0.5/log0.5

(logx/log0.5) - 2 = y

but the correct answer is \[\sqrt[(x-2)]{0.5}\]

Answer 2

heelp D:

Answer 3

@asnaseer do you have a clue as to how to get the correct answer? :$

Answer 4

how sure are you that the correct answer is \(\sqrt[(x-2)]{0.5}\)?

Answer 5

sure as in it's written in the back of my book...

Answer 6

well it does not look correct to me.

Answer 7

maybe there is a printing error in your book?

Answer 8

really? oh.. okay, thank you!