Question

If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and third equations, then the second and third equations.

Answer 1

x – y + 2z = –2
2x + 2y + z = 7
3x + 3y – z = 3

Answer 2

choices are:

Answer 3

2x + 2y = 7
3x + 3y = 3

2x + 2y = 7
5x + 5y = 10

7x + 5y = 4
3x + 3y = 3

7x + 5y = 4
5x + 5y = 10

Answer 4

for first and third equations...: by what do you multiply the third equation in order to eliminate z when the two equations are added?

Answer 5

2

Answer 6

yes, and what's the result when you add them after multiplying the third eqn. by 2?

Answer 7

-5x - 7y = -8

Answer 8

I got C, is that right?

Answer 9

x – y + 2z = –2
+2(3x + 3y – z = 3)
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Answer 10

x - y + 2z = -2
6x + 6y -2z = 6

Answer 11

so 7x + 5y = 4

Answer 12

so it's C or D

now add equations 2 and 3

Answer 13

so it's either c or d hmm

Answer 14

okay

Answer 15

5x + 5y = 10

Answer 16

it's d?

Answer 17

yep

Answer 18

thanks!!

Answer 19

sure