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Solve: 2x2+200=0
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What you always ought to start such problems with is isolating the variable
Are imaginary answers allowed?
Not sure maybe....
Well, in any case, start by getting x^2 by itself on one side
I got it! Subtract 200 from both sides 2x2=-200 Divide by 2 2x2/2=-200/2 The 2's cancel on the right side 2x=-100 Then divide by 2 on both sides 2x/2=-100/2 The 2's cancel on the right side, then you divide -100 by 2 x=-50
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Whoa, wait.. That was supposed to be x^2?
\[2x ^{2}+200=0\]\[2x ^{2}=-200\]\[x ^{2}=-100\]\[x=\pm10i\]
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