The perimter of the rectangle is thirty feet. The length is three feet longer than the width. Find the demensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width. What is length? What is width?
Okay so lets draw a picture, pictures always help in questions like this. So tell me what perimeter is..|dw:1349752474003:dw|
i have 2(x+y)=thirty x= y+three 2(y+three+y)=thirty 2y+three=27
i think its 2 by 25
I got a different answer, so this is what I did: |dw:1349752942242:dw| So y=x+3 and 2(y+x)=30 (the perimeter) We can substitute y=x+3 into the second equation so it will be 2y+2x=30 so 2(x+3)+2x=30 which is 2x+6+2x=30 so 4x+6=30 subtract 6 4x=24 divide 24 by 4 x=6
You can then plug x back into the equation to solve for Y
ok so the lentgh is 24 the width is 2
i dont know how i got 25
i think i miss count
How'd you get 2?
for the width is x 2 or well idk
if x is the width and x=6 then 6 is the width If the length is the width + 3 then x+3=y (y is the length) 6+3=9 so the width is 6 and the length is 9? confused by that?
ok i seee 4/24 is 6
nope i see my errors but i think i was getting warm lol
and if you add the sides, 6+6+9+9 that equals 30, which is what the question said so you can check that way.
you add the three feet to 6 to get 9
Yup, since the problem said "The length is three feet longer than the width."
ok it says the first equation 2x+2y=? and second equat x=y+?
so i put thirty and three for the 1st and 2nd equat where the ? marks are at...
2x+2y=thirty x=y+three
do you see?
It should be y=x+3 if you're doing by my diagram, but you just switched the x's and y's around. if you solve what you just put you should get the same answers
oh ok thats ok it still camee out right
So you know what the width and length are?
6 and 9 right
Yup!
yeeeaaa
you are smart i am trying at last i attempt to try do you havee time for 2 more prob?
Sure! I'm not sure if you should do this but clicking best repose may show others where the answer is encase they're looking at this problem. but Yeah I have time for some more.
ok i didnt know ok the probelm is Shade the solution set to th system of inequality. x+three y>-2 2x+ ygreater than = to three
x+3y>-2 \[2x+y \ge 3\] so those are the two equations, now you need them in slope intercept form or y=mx+b. Okay?
ok so do i gt y by itself
Yup! now do that for both equations
three y=x+-2
okay so 3y=x+-2 Now you can divide both sides by 3 so you're left with y>1/3x+-2/3 For the first quation
do i divide three into -2/three
\[y > 1/3x -2/3\] -2/3 is a fraction so you don't need to divide it out
well 1/three divide by three is = 1
i hat this graphing it makes my head hurt but will keep trying
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