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x² + 16 = 0 Solve.
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subtract 16 from both sides..what do you get?
x² = -16
right. now take the square root of both sides
answer is fake, I mean imaginary
yeah so its i?
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close. i is just square root of -1
hmm..
\[\sqrt{-16} \implies i \times \sqrt {16}\] got it?
no im still not understanding
i assume you know what the square root of 16 is?
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\[\sqrt{-1}*\sqrt{-16}\]
4
i x 4?
nope..remember a square is positive and negative so square root of 16 is \(\pm\) 4
so \[\sqrt{-16} \implies i \times \pm 4 \implies \pm 4i\] got it now?
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ohhh yeah
thanx
welcome
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