Simplify this expression. Problem is in the comments.
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OpenStudy (firejay5):
\[\frac{ 6x }{ 9(x + y) }\]
OpenStudy (anonymous):
6x/9x+9y
2x/3x+3y or 2x/3(x+y)
OpenStudy (firejay5):
\[\frac{ 8x } {18(x+y) }\]
OpenStudy (firejay5):
@Copythat You might as well just stay on this question, I have more for you to do
OpenStudy (anonymous):
..... I'm not here to do your homework for you. I'll walk you through it and then you can try some of them
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OpenStudy (anonymous):
8x/18x+18y
4x/9x+9y or 4x/9(x+y)
OpenStudy (firejay5):
I mean there's 10, and I'll give you 5 of the 10
OpenStudy (firejay5):
@Copythat \[\frac{ 3g^3h^3 }{ 6g }\]
OpenStudy (firejay5):
they g and h is raised to the power of 3
OpenStudy (anonymous):
Start by simplifying: 3/6 is equal to __________
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OpenStudy (firejay5):
is equal to 1/2
OpenStudy (anonymous):
right. so you have g^3h^3/2g
OpenStudy (anonymous):
Now whenever you have variables in both the numerator and the denominator, you can subtract. Here you have g^3 in the numerator and g^1 in the denominator. Subtract 1 from 3 and you get g^_____
OpenStudy (anonymous):
*not variables, exponents
OpenStudy (firejay5):
2
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OpenStudy (firejay5):
-2
OpenStudy (anonymous):
positive 2
OpenStudy (firejay5):
ok
OpenStudy (firejay5):
so it's \[\frac{ 1g^2h^3 }{ 2 }\]
OpenStudy (anonymous):
Correct, but you don't need the 1 in front of the g
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OpenStudy (firejay5):
4u^4v^4/24u
OpenStudy (anonymous):
nice job
OpenStudy (firejay5):
is it correct
OpenStudy (anonymous):
If its 4u^4v^4/24u and not (4u^4v^4)/24u, then it is correct
OpenStudy (anonymous):
Actually either way would work.
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