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Mathematics 13 Online
OpenStudy (firejay5):

Simplify this expression. Problem is in the comments.

OpenStudy (firejay5):

\[\frac{ 6x }{ 9(x + y) }\]

OpenStudy (anonymous):

6x/9x+9y 2x/3x+3y or 2x/3(x+y)

OpenStudy (firejay5):

\[\frac{ 8x } {18(x+y) }\]

OpenStudy (firejay5):

@Copythat You might as well just stay on this question, I have more for you to do

OpenStudy (anonymous):

..... I'm not here to do your homework for you. I'll walk you through it and then you can try some of them

OpenStudy (anonymous):

8x/18x+18y 4x/9x+9y or 4x/9(x+y)

OpenStudy (firejay5):

I mean there's 10, and I'll give you 5 of the 10

OpenStudy (firejay5):

@Copythat \[\frac{ 3g^3h^3 }{ 6g }\]

OpenStudy (firejay5):

they g and h is raised to the power of 3

OpenStudy (anonymous):

Start by simplifying: 3/6 is equal to __________

OpenStudy (firejay5):

is equal to 1/2

OpenStudy (anonymous):

right. so you have g^3h^3/2g

OpenStudy (anonymous):

Now whenever you have variables in both the numerator and the denominator, you can subtract. Here you have g^3 in the numerator and g^1 in the denominator. Subtract 1 from 3 and you get g^_____

OpenStudy (anonymous):

*not variables, exponents

OpenStudy (firejay5):

2

OpenStudy (firejay5):

-2

OpenStudy (anonymous):

positive 2

OpenStudy (firejay5):

ok

OpenStudy (firejay5):

so it's \[\frac{ 1g^2h^3 }{ 2 }\]

OpenStudy (anonymous):

Correct, but you don't need the 1 in front of the g

OpenStudy (firejay5):

4u^4v^4/24u

OpenStudy (anonymous):

nice job

OpenStudy (firejay5):

is it correct

OpenStudy (anonymous):

If its 4u^4v^4/24u and not (4u^4v^4)/24u, then it is correct

OpenStudy (anonymous):

Actually either way would work.

OpenStudy (firejay5):

2u/4(u + v) = u/2u+2v

OpenStudy (firejay5):

@Copythat

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