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5y-3/5=4/5
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Add both sides by 3/5, then divide both sides by 5. We have to do that because we want y to be alone. Make sense?
can you write that out ?
im only in 8th grade and we just started learnin this
i got 7 more questionss >.< and im tired
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\[\huge5y-\frac{3}{5}=\frac{4}{5}\]\[\huge5y-\frac{3}{5} + \frac{3}{5}=\frac{4}{5}+\frac{3}{5}\]\[\huge5y=\frac{7}{5}\]\[\huge \frac{5y}{5}=\frac{\frac{7}{5}}{5}\]\[\huge y=\frac{\frac{7}{5}}{5} = \frac{7}{25}\]Does this help?
yes
Do you understand the last step?
Yes i understand now thank you
No problem.
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